Struct std::slice::IterMut
[−]
[src]
pub struct IterMut<'a, T> where T: 'a {
// some fields omitted
}1.0.0Mutable slice iterator.
Examples
Basic usage:
fn main() { // First, we declare a type which has `iter_mut` method to get the `IterMut` // struct (&[usize here]): let mut slice = &mut [1, 2, 3]; // Then, we iterate over it and increment each element value: for element in slice.iter_mut() { *element += 1; } // We now have "[2, 3, 4]": println!("{:?}", slice); }// First, we declare a type which has `iter_mut` method to get the `IterMut` // struct (&[usize here]): let mut slice = &mut [1, 2, 3]; // Then, we iterate over it and increment each element value: for element in slice.iter_mut() { *element += 1; } // We now have "[2, 3, 4]": println!("{:?}", slice);
Methods
impl<'a, T> IterMut<'a, T>
fn into_slice(self) -> &'a mut [T]1.4.0
View the underlying data as a subslice of the original data.
To avoid creating &mut references that alias, this is forced
to consume the iterator. Consider using the Slice and
SliceMut implementations for obtaining slices with more
restricted lifetimes that do not consume the iterator.
Examples
Basic usage:
fn main() { // First, we declare a type which has `iter_mut` method to get the `IterMut` // struct (&[usize here]): let mut slice = &mut [1, 2, 3]; { // Then, we get the iterator: let mut iter = slice.iter_mut(); // We move to next element: iter.next(); // So if we print what `into_slice` method returns here, we have "[2, 3]": println!("{:?}", iter.into_slice()); } // Now let's modify a value of the slice: { // First we get back the iterator: let mut iter = slice.iter_mut(); // We change the value of the first element of the slice returned by the `next` method: *iter.next().unwrap() += 1; } // Now slice is "[2, 2, 3]": println!("{:?}", slice); }// First, we declare a type which has `iter_mut` method to get the `IterMut` // struct (&[usize here]): let mut slice = &mut [1, 2, 3]; { // Then, we get the iterator: let mut iter = slice.iter_mut(); // We move to next element: iter.next(); // So if we print what `into_slice` method returns here, we have "[2, 3]": println!("{:?}", iter.into_slice()); } // Now let's modify a value of the slice: { // First we get back the iterator: let mut iter = slice.iter_mut(); // We change the value of the first element of the slice returned by the `next` method: *iter.next().unwrap() += 1; } // Now slice is "[2, 2, 3]": println!("{:?}", slice);