Struct std::slice::Iter
[−]
[src]
pub struct Iter<'a, T> where T: 'a {
// some fields omitted
}1.0.0Immutable slice iterator
Examples
Basic usage:
fn main() { // First, we declare a type which has `iter` method to get the `Iter` struct (&[usize here]): let slice = &[1, 2, 3]; // Then, we iterate over it: for element in slice.iter() { println!("{}", element); } }// First, we declare a type which has `iter` method to get the `Iter` struct (&[usize here]): let slice = &[1, 2, 3]; // Then, we iterate over it: for element in slice.iter() { println!("{}", element); }
Methods
impl<'a, T> Iter<'a, T>
fn as_slice(&self) -> &'a [T]1.4.0
View the underlying data as a subslice of the original data.
This has the same lifetime as the original slice, and so the iterator can continue to be used while this exists.
Examples
Basic usage:
fn main() { // First, we declare a type which has the `iter` method to get the `Iter` // struct (&[usize here]): let slice = &[1, 2, 3]; // Then, we get the iterator: let mut iter = slice.iter(); // So if we print what `as_slice` method returns here, we have "[1, 2, 3]": println!("{:?}", iter.as_slice()); // Next, we move to the second element of the slice: iter.next(); // Now `as_slice` returns "[2, 3]": println!("{:?}", iter.as_slice()); }// First, we declare a type which has the `iter` method to get the `Iter` // struct (&[usize here]): let slice = &[1, 2, 3]; // Then, we get the iterator: let mut iter = slice.iter(); // So if we print what `as_slice` method returns here, we have "[1, 2, 3]": println!("{:?}", iter.as_slice()); // Next, we move to the second element of the slice: iter.next(); // Now `as_slice` returns "[2, 3]": println!("{:?}", iter.as_slice());